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690x-12420x^2=0
a = -12420; b = 690; c = 0;
Δ = b2-4ac
Δ = 6902-4·(-12420)·0
Δ = 476100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{476100}=690$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(690)-690}{2*-12420}=\frac{-1380}{-24840} =1/18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(690)+690}{2*-12420}=\frac{0}{-24840} =0 $
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